If u (x) = negative 2 x squared and v (x) = startfraction 1 over x endfraction, what is the range of (u circle v) (x)?

a(one-third, 0)

b(3, infinity)

c(negative infinity, 3)

d(negative infinity, positive infinity)

Step-by-step explanation:

As per the given question, and .

Hence,  (u circle v) (x) = u{v(x)} =

The range of the function, (u circle v) (x) means the set of the values of x so that we will be able to get a proper finite, countable and exact value of the function.

For the above function, (u circle v) (x) we can not get a proper value of the function for x = 0.

Hence, the options A, C, D can not be the range of the function, since it contains 0.

The range of the given function will be the option B, since it does not contain the value 0.

false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms