Direct mail advertisers send solicitations ("junk mail") to thousands of potential customers in the hope that some will buy the company's product. the response rate is usually quite low. suppose a company wants to test the response to a new flyer and sends it to 1140 people randomly selected from their mailing list of over 200,000 people. they get orders from 122 of the recipients. use this information to complete parts a through d. create a 95% confidence interval for the percentage of people the company contacts who may buy something. (show your work. step by step)

(0.089, 0.125)

Step-by-step explanation:

Confidence interval for population proportion is given by :-

, where n= sample size.

= Sample proportion.

z*= Critical z-value.

Let p be the population proportion of people the company contacts who may buy something.

As per given , sample size : n= 1140

Number of recipients ordered = 122

Then,

Critical value for 95% confidence interval = z*= 1.96 (By z-table)

So , the 95% confidence interval for the percentage of people the company contacts who may buy something:

Hence, the 95% confidence interval for the percentage of people the company contacts who may buy something = (0.089, 0.125)

y - y1 = m(x- x1)

y - (-5) = 2/3(x -0)

y + 5 = 2/3x

y = 2/3x - 5

10 miles

step-by-step explanation: