Aperson rolls a standard six-sided die 9 times. in how many ways can he get 3 fours, 5 sixes, and 1 two?

There are 5040 ways he get 3 fours, 5 sixes, and 1 two.

Step-by-step explanation:

Given : A person rolls a standard six-sided die 9 times.

To find : In how many ways can he get 3 fours, 5 sixes, and 1 two?

Solution :

A person rolls a standard six-sided die 9 times.

So, total number of ways die roll is 9! ways.

In die 4 comes 3 times.

So, ways of getting 4 is 3!

In die 6 comes 5 times.

So, ways of getting 6 is 5!

In die 2 comes 1 times.

So, ways of getting 2 is 1!

Total number of ways is given by,

Therefore, there are 5040 ways he get 3 fours, 5 sixes, and 1 two.

answer

the correct answer is

explanation

the given function is

the excluded values are obtained by solving:

we factor to obtain:

the excluded values are

no one knows lol

step-by-step explanation: