If a, b, and c are integers between 1 and 10 (inclusive), how many different combinations of a, b, and c exist such that a

Step-by-step explanation:

A, B and C are integers between 1 and 10  such that A<B<C.

The value of A can be minimum 1 and maximum 8.

If A = 1, B = 2, then C can be one of 3, 4, 5, 6, 7, 8, 9, 10 (8 options).

If A = 1, B = 3, then C has 7 options (4, 5, 6, 7, 8, 9, 10).

If A = 1, B = 4, then C has 6 options (5, 6, 7, 8, 9, 10).

If A = 1, B = 5, then C has 5 options (6, 7, 8, 10).

If A = 1, B = 6, then C has 4 options (7, 8, 9, 10).

If A = 1, B = 7, then C has 3 options (8, 9, 10).

If A = 1, B = 8, then C has 2 options (9, 10).

If A = 1, B = 9, then C has 1 option (10).

So, if A = 1, then the number of combinations is

Similarly, if A = 2, then the number of combinations is

If A = 3, then the number of combinations is

If A = 4, then the number of combinations is

If A = 5, then the number of combinations is

If A = 6, then the number of combinations is

If A = 7, then the number of combinations is

If A = 3, then the number of combinations is

Therefore, the total number of combinations is

Thus, the required number of different combinations is 120.

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Question : ow many types of zygotic combinations are possible between a cross AaBBCcDd × AAbbCcDD?

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step-by-step explanation:

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