Nuri joins a game for a car. the rule is that nuri pick one key from box either a, b, or c. a box has two keys but only one can be used. b box has three keys but only one can be used. c box has two keys but none of them can be used. what is the probability that nuri can win the car?

0.278

Step-by-step explanation:

Given that Nuri joins a game for a car. The rule is that Nuri pick one key from box either A, B, or C. A box has two keys but only one can be used. B box has three keys but only one can be used. C box has two keys but none of them can be used.

Each box is equally likely to be selected.

In other words

If A is selected then probability of winning is using the correct key out of two keys i.e. 0.5

If B is selected then probability of winning is using the correct key out of three keys i.e. 0.333

If c is selected then probability of winning is using the correct key out of two keys i.e. 0.00

So the probability that Nuri can win the car

=

y -5 = (-1/4)(x + 8)

step-by-step explanation: