If x =− 2 and x^2+y^2+3xy =-5 , then find y

y = 3

Step-by-step explanation:

Given:

x²+y²+3xy =-5  and x = -2

Substituting x=-2 into the equation:

(-2)² + y² + 3y(-2) = -5

4 + y² - 6y = -5

y² - 6y +4 + 5 = 0

y² - 6y +9  = 0   (solve by factorization)

(y-3) (y-3) = 0

y = 3

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

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step-by-step explanation:

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