The vertices of parallelogram abcd are located at points a(-2,-1), b(6,1), c(10,7), and d(2,5). which of the following statements are true?
select all that apply.

The statements which are true are:

(6, 6) is the midpoint of CD

(4, 3) is the intersection point of diagonals of parallelogram

Solution:

The mid point (x,y) =

A(-2, -1) and B(6, 1)

Thus statement 1 is wrong

B(6, 1) and C(10, 7)

Thus statement 2 is wrong

Here ,

= 10

= 2

= 7

=5

now substituting these values,

mid point of CD  =

mid point of CD  =  

mid point of CD  =

Therefore (6, 6) is the midpoint of CD

Statement 3 is correct

A = (-2, -1) and D = (2, 5)

Thus statement 4 is wrong

Let AC and BD be the diagonals of parallelogram

The diagonals of a parallelogram bisect each other, therefore, the point of intersection is the midpoint of either.

Midpoint of AC:

A = (-2, -1) and C(10, 7)

Thus statement 5 is correct

use formula for the circle a=3.14

step-by-step explanation:

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph