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y= x^2- 2x - 19
y + 4x = 5
the pair of points representing the solution set of this system of equations is (-6, 29) and

answer:

(4, - 11)

step-by-step explanation:

given the 2 equations

y = x² - 2x - 19 → (1)

y + 4x = 5 → (2)

substitute y = x² - 2x - 19 into (2)

x² - 2x - 19 + 4x = 5, that is

x² + 2x - 19 = 5 ( subtract 5 from both sides )

x² + 2x - 24 = 0 ← in standard form

(x + 6)(x - 4) = 0 ← in factored form

equate each factor to zero and solve for x

x + 6 = 0 ⇒ x = - 6

x - 4 = 0 ⇒ x = 4

substitute these values into (2) and solve for y

x = - 6 : y - 24 = 5 ⇒ y = 29 ⇒ (- 6, 29 )

x = 4 : y + 16 = 5 ⇒ y = - 11 ⇒ (4, - 11 )

the solutions are (- 6, 29 ) and (4, - 11 )

answer:

im not sure

step-by-step explanation:

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

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step-by-step explanation: