Consider the linear system of equations y = 2/5x - 1 and 2x -3y + 1 = 0

The solution is the point (-5,-3)

Step-by-step explanation:

The complete question is

Consider the linear system of equations y = 2/5x - 1 and 2x -3y + 1 = 0

The solution of the system of equations is?

we have

----> equation A

----> equation B

Solve by substitution

substitute the equation A in equation B

solve for x

Multiply by 5 both sides to remove the fraction

subtract 20 both sides

divide by 4 both sides

Find the value of y

The solution is the point (-5,-3)

x = 10.1

step-by-step explanation:

all of the angles of a tirangle add up to 180º

180 - 65 = 115 (since we already know the value of one angle)

(2x + 7) + (8x + 7) = 115

(combins like terms) 10x + 14 = 115

(isolate the variable subtract 14 from both sides): 10x = 101

(find the variable divide both sides by 10): x = 101/10

x = 10.1