? This is the question.![\sqrt[3]{27a^{12}}](/tpl/images/0443/8650/2af6f.png)
![\sqrt[n]{a*b}=\sqrt[n]{a} \sqrt[n]{b}](/tpl/images/0443/8650/2feb8.png)
![\sqrt[3]{27a^{12}} =\sqrt[3]{27} \sqrt[3]{a^{12}}](/tpl/images/0443/8650/ef1a0.png)
![\sqrt[n]{x} =x^{\frac{1}{n}}](/tpl/images/0443/8650/70624.png)
![\sqrt[3]{27} \sqrt[3]{a^{12}} =3*(a^{12})^{\frac{1}{3}}](/tpl/images/0443/8650/54d76.png)
What is the cube root of 27a^l2?
-3a4
-3a
3a
3a*...
Answers: 3
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