In a certain algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. there are 8 students who play both sports. what is the probability that a student chosen randomly from the class plays basketball or baseball?

Probability that a student chosen randomly from the class plays basketball or baseball is   or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

---------------(1)

where

P(A) = Probability of choosing  a student playing basket ball

P(B) =  Probability of choosing  a student playing base ball

P(A \cap B) =  Probability of choosing  a student playing both the games

Finding  P(A)

P(A) =

P(A) = --------------------------(2)

Finding  P(B)

P(B) =

P(B) = ---------------------------(3)

Finding

P(A) =

P(A) = -----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

answer: 21$

step-by-step explanation:

$42 / $14 = 3   (ratio 3: 1)

$7 x 3 = $21