Plz hurry solve this system of equations:
2x + 3y = 13
5x – 3y = 1
a. (3, 14/3)
b (3,7/3)
c (3,2)
d. (2,3)
e (2, 7/2)
✏️

D. (2,3)

THIS IS USING ELIMINATION

1. 2x + 3y = 13

+

2. 5x - 3y = 1

7x = 14

divide by 7 on both sides

3. x = 2

put the 2 back in to the x of the EASIEST equation to solve for so use equation 1

2 (2) + 3y = 13

4 + 3y = 13

-4 -4

3y = 9

divide by 3 on both sides

y = 3

put it back in to equation number 2 to chech

5 (2) - 3 (3) = 1 ?

10 - 9

= 1 it is checked and is true. it is correct so the answer is D

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.

10 - 75

step-by-step explanation:

there's nothing attached so it's most likely anything in that range.