The manufacturerâs suggested retail price (msrp) of a certain item is $60. store a sells the item for 20 percent more than the msrp. the regular price of the item at store b is 30 percent more than the msrp, but the item is currently on sale for 10 percent less than the regular price. if sales tax is 5 percent of the purchase price at both stores, what is the result when the total cost of the item at store b is subtracted from the total cost of the item at store a? a. $0b. $0.63c. $1.80d. $1.89e. $2.10

C. $1.80

Step-by-step explanation:

Given:

MSRP of a certain item = $60

Percentage of Selling by store A = 20%

Percentage amount will be =

Sales tax = 5% on purchase price

Amount of sales tax =

Total Cost of item at Store A is MSRP of a certain item plus Percentage amount of selling the item plus Amount of Sales tax.

framing in equation form we get;

Total Cost of item at Store A =

Also Given:

Percentage of Selling by store B = 30%

Percentage amount will be =

Regular price of item at store B =

Percentage of discount of item at store B = 10% on regular price

Amount of discounted item at store B =

Now regular price of item with discount at store B will be equal to Regular price of item at store B minus Amount of discounted item.

regular price of item with discount at store B =

Sales tax = 5% on purchase price

Amount of sales tax =

Total Cost of item at Store B is regular price of item with discount at store B plus Amount of Sales tax.

framing in equation form we get;

Total Cost of item at Store B =

The result when total cost of the item at Store B is subtracted from the total cost of the item at Store A  = $73.2 - $75 = $1.80.

Hence the result is $1.80.

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range: