In triangle $abc$, $bc = 20 \sqrt{3}$ and $\angle c = 30^\circ$. let the perpendicular bisector of $bc$ intersect $bc$ and $ac$ at $d$ and $e$, respectively. find the length of $de$.

DE=10

Step-by-step explanation:

Given that in triangle ABC, $BC = 20 \sqrt{3}$ and $\angle C = 30^\circ$. Let the perpendicular bisector of $BC$ intersect $BC$ and $AC$ at $D$ and $E$,

To find length of DE

Please refer to the attachment for solution

Since perpendicular bisector we have DC = 1/2 BC = 10 sqrt 3

Using right triangle CDE, we get DE = 10

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step-by-step explanation: