Afair coin is tossed 29 times. in how many outcomes do at least 2 tails occur?

a. 536,870,476
b. 1
c. 536,870,883
d. 536,870,882
e. 406
f. none of the above

d. 536,870,882

Step-by-step explanation:

The number of outcomes in which at least 2 tails occur (N(t>1)) is given by the total number of possible outcomes (N) subtracted by the number of possibilities in which one or none tails occur.

For each throw, there are two possible outcomes. The total number of outcomes is:

There is only one outcome where no tails occur, while there 29 outcomes in which only one tails occur (one for each toss).

Therefore, the number of outcomes in which at least 2 tails occur is:

d. 536,870,882

b. 2 and 4

step-by-step explanation:

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: