(20pt an and will mark as brainliest)

The Proof is given below.

Step-by-step explanation:

Given:

P is the center of Circle

∠ONE ≅ ∠TEN

To Prove:

∠5 ≅ ∠6

Proof:

Exterior Angle Theorem:

Exterior Angle Property of a Triangle states that measure of exterior angle of a triangle is equals to the sum of measures of its interior opposite angles.

STATEMENT                                                   REASON

1. So In ΔONE,

1. Exterior Angle Property of a Triangle.

2. Similarly In ΔTEN,

  2. Exterior Angle Property of a Triangle.

3. But , ∠ONE ≅ ∠TEN                               3. Given

4. And P is the center of circle So

                                        4.radius of same circle

5. ΔPEN is an Isosceles triangle,

∴ ∠ 1 ≅ ∠ 2                                                  5. Isosceles triangle property

6. ∴ ∠5 ≅ ∠6                                               6. From 3 and 5 Transitive Property.........Proved

im here

step-by-step explanation:

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2