Acat gave birth to 4 kittens. three of the kittens had different masses between 147 and 159 kg and one kitten had a mass of 57kg . how will the removal of the kitten affect the mean and median?

they both decrease and the mean decreases more than the median

Step-by-step explanation:

Both the mean and median will increase, but the mean will increase by more than the median.

Step-by-step explanation:

Removing the kitten will increase the median a little bit, because the median shifts from between two data points to the higher of the two data points.

Removing the kitten will increase the mean significantly, because the total weight will decrease by only 57 g , and the number of kittens decreases by 1.

                                                  So

Both the mean and median will increase, but the mean will increase by more than the median.

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺

804.75

step-by-step explanation: