Find the 4^\text{th}4 th 4, start superscript, start text, t, h, end text, end superscript term in the sequence.

If the sequence is the following:

c(n) = -7+6 (n-1)

c(1) = -7 + 6(1-1) = -7 + 6(0) = -7+0 = -7

c(2) = -7 + 6(2-1) = -7 + 6(1) = -7 +6 = -1

c(3) = -7 + 6(3-1) = -7 + 6(2) = -7 + 12 = 5

c(4) = -7 + 6(4-1) = -7 + 6(3) = -7 + 18 = 11

Step-by-step explanation:

If the sequence is the following:

c(n) = -7+6 (n-1)

And we want to find the first four terms, so w ejust need to replace the values for n =1,2,3,4 and see what we got:

c(1) = -7 + 6(1-1) = -7 + 6(0) = -7+0 = -7

c(2) = -7 + 6(2-1) = -7 + 6(1) = -7 +6 = -1

c(3) = -7 + 6(3-1) = -7 + 6(2) = -7 + 12 = 5

c(4) = -7 + 6(4-1) = -7 + 6(3) = -7 + 18 = 11

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)