4. the regression line for this bivariate data set is = 19.41 + .17x. what is the residual for the point with an x-value of 68? x 56 45 68 49 58 63 66 62 y 28 25 34 30 32 36 23 29

3.03

Step-by-step explanation:

xy

5628

4525

6834

4930

5832

6336

6623

6229

slope0.174993175

Intercept19.40977341

is the regression line

As per line, we can find y for x=68 as

For x=68

y actual = 34

y predicted = 30.97

Residual = 34-30.97

= 3.03

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

dont know

step-by-step explanation: