What is the horizontal asymptote of the function f (x) = startfraction (x minus 2) over (x minus 3) squared endfraction?

y=1

Step-by-step explanation:

See asymptote is a tangent to a function at infinity.

The function of x provided is

Now just roughly plot this function on graph by using these points mentioned.

Firstly x = 3 is not in domain of function because it's making denominator zero. Now if we calculate value of function around 3 then it tends to plus infinity.

If we move forward from 3 then value of function decreases from infinity and tends to 1.

Also  x = 2 is root of the function and behind 2 the function value increases and tend toward y =1.

Thus horizontal asymptote is y = 1.