Write an equation of the perpendicular bisector of the segment with endpoints q(−2,0)
and r(6,12)

The equation of the perpendicular bisector of the segment with endpoints Q(−2,0)  and R(6,12) is; y = -²/₃x + ²²/₃

We are given the endpoints of the segment as;

Q(-2, 0) and R(6, 12)

Coordinates of the midpoint of the segment is;

((-2 + 6)/2), ((0 + 12)/2)

⇒ (2, 6)

Now, the formula for the slope of the segment QR is;

m' = (y₂ - y₁)/(x₂ - x₁)

m' = (12 - 0)/(6 - (-2))

m' = 3/2

Now, the slope of the perpendicular bisector will be;

m = -1/m'

m = -1/(3/2)

m = -2/3

Thus, using equation of line in slope intercept form gives;

y = mx + c

y = -²/₃x + c

Let us put (2,6) for x and y respectively;

6 = -²/₃(2) + c

6 = -⁴/₃ + c

c = 6 + ⁴/₃

c = ²²/₃

Thus, equation of the perpendicular bisector of the segment with endpoints Q(−2,0)  and R(6,12) is; y = -²/₃x + ²²/₃

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the correct answer is semicircle

step-by-step explanation:

the answer is semicircle because the shorter arc joining two points on the circumference of a circle is known as the minor arc, the larger arc is called the major arc, and a semicircle is a half circle, formed by cutting a whole circle along a diameter line.

hope i .

after simplifying it i got: -36.25 as my answer. hope that !