What is the equation of the line described below written in slope-intercept form? the line passing through point (2,2) and perpendicular to the line whose equation is y = x

The equation of line passing through point (2 , 2) and perpendicular to line y = x is  y = - x + 4   .

Step-by-step explanation:

Given as :

The line equation is y = x

Now, equation of line in slope-intercept form y = m x + c

where m is the slope of line and c is y-intercept

Comparing given line equation with standard line equation

The slope of line y = x is m = 1

Again

Other line is passing through point (2 ,2) and is perpendicular to line y = x

Let The slope of other line = M

∵ From perpendicular lines property

Product of slope of lines = - 1

i.e m × M = - 1

Or , M =

Or, M =

∴  M = - 1

Now, Equation of other line in point-slope form

The other line is passing through point (2 , 2) and slope M = - 1

So, y - = M × (x - )

Or, y - 2 = - 1 × ( x - 2 )

Or, y - 2 = - x + 2

Or, y = - x + 2 + 2

Or, y = - x + 4

Hence, The equation of line passing through point (2 , 2) and perpendicular to line y = x is  y = - x + 4   . Answer

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval