Y= 2/5x + 1
y = -2/5 - 3
what is the point of intersection

The point of intersection of given polynomials is ( - 5 , - 1 ) .

Step-by-step explanation:

Given as :

The two polynomials are

y = x + 1            ........A

y = x - 3         ........B

Let The point of intersection = p = x,y

Now, Solving the equation A and B

So, Putting the value of y from Eq A into Eq B

i.e x + 1 = x - 3

Rearranging the equation

Or, x - ( x) = - 3 - 1

Or, x + x = - 3 - 1

Or, ( +   ) x = - 4

Or, ( ) x = - 4

Or,  ( ) x = - 4

∴  x =

i.e x = - 5

So The value of x = - 5

now put the vale of x into eq B

∵y = x - 3    

So, y = × (-5) - 3    

Or, y = - 3

Or, y = 2 - 3

i.e y = - 1

So The value of y = - 1

So,The point of intersection = p = x , y = - 5 , - 1

Hence, The point of intersection of given polynomials is ( - 5 , - 1 ) . Answer

answear:

a

step-by-step explanation: a

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.