3. consider the following:
a. a game was advertised as having a probability of 0.4 of winning. you know that the game involved five cards with a different digit on each card. describe a possible game involving the
cards that would have a probability of 0.4 of winning.
b. a second game involving the same five cards was advertised as having a winning probability of 0.05. describe a possible game that would have a probability of 0.05 or close to 0.05
of winning.

a.) Digits on the 5 cards are 1,2,3,4,5. You pick one card. You win if you pick a card having an even number.

b) Digits on the 5 cards are 1,2,3,4,5. You pick two cards. You win if you pick fist the card having number 5 and then the card having number 4.  

Step-by-step explanation:

a) The probability of picking an even number is:

picking a card with even numbers (picking 2 or 4)  / all cards (1,2,3,4,5)

b) Probability of picking the card having 5 first

Then the probability of picking the card having number 4 from the remaining 4 cards:

Combined probability, that is picking first number 5 and then number 4 is

6x = 48

i hope this . 6 cards each and a total of $48. dvide each side by 6 and you will have your answer.

we can't see all full 4 options, but if this is the full option, than the very left one is correct:

-2/5 * -3 3/4

remake the question, adding a picture of all the question, or write down the full left and right answers.