How do you find the last digit of a exponent powering 2

  2^(1 + ((n-1) mod 4)) mod 10

Step-by-step explanation:

We presume you want the last digit of the power of 2, not the last digit of the exponent. Powers of 2 mod 10 are ...

2^0 : 1

2^1 : 2

2^2 : 4

2^3 : 8

2^4 : 6

2^5 : 2 . . . .  and the sequence repeats: 2, 4, 8, 6, ...

That is, ...

  (2^n) mod 10 = 2^(1 + ((n-1) mod 4)) mod 10 . . . for n > 0

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

x=6 and x=3

beep beep imma sheep