Afamily of 2 adults and 4 children is going to an amusement park. admission is a 21 point 75 for adults and 15 point 25 for children, what is the total cost of the families admission?

Step-by-step explanation:

The number of adults in the family that is going to the amusement park is 2.

The number of children in the family that is going to the amusement park is 4.

Admission is a 21 point 75 for adults and 15 point 25 for children. This means that the admission cost for each adult is 21.75 and the admission cost for each adult is 15.25. Therefore,

The total cost of admission for the 2 adults would be

21.75 × 2 = 43.5

The total cost of admission for the 4 children would be

15.25 × 4 = 61

Therefore, the total cost of the families admission would be

43.5 + 61 = 104.5

1696 hundred thousand

step-by-step explanation:

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240