Mathematics, 10.01.2020 23:31 fletcherjf3

The graph of which function passes through (0,4) and has a minimum value at (startfraction 3 pi over 2 endfraction, 3)? f (x) = sine (x) + 4 f (x) = cosine (x) + 3 f (x) = negative 3 sine (x) f (x) = 4 cosine (x)

Answers: 2

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Answer from: kyleeeeee94

f(x) = sin(x) + 4 Let me know if you don't see why.

Step-by-step explanation:

As much as I hate it I think it might be best to check each one.

sin(x) has a point at (0,0) so that's not right.

sin(x)+4 has (0,4) as a point and a minimum at (3*pi/2+2*pi*n,3) where n is some integer. if we have n = 0 then it becomes (3*pi/2, 3) So that looks like our answer.

cos(x) + 3 has a point at (0,4) then minimums at (pi+2*pi*n, 2) the y coordinate is wrong so this won't work

-3sin(x) has a point at (0,0) so that's wrong

4cos(x) has a point at (0,4) then minimums at (pi+2*pi*n, -4) which again has the wrong y value so this is wrong.

Let me know if you don't understand how I got the results I did, I would be happy to explain.

Answer from: ghari112345

f(x) = sin(x) + 4

Step-by-step explanation:

The right choice is the first one.

You can rapidly get the answer by identifying the interception with the vertical axis.

The problem specifies that the functions passes through (0,4), which is a vertical interception. So, vertical interceptions appears in the equations as an independent term, and the only function among options that has an independent term of 4 is the first choice.

In addition, the graph of the function is attached, there you could observe the interception point with the vertical axis.

$The graph of which function passes through (0,4) and has a minimum value at (startfraction 3 pi over$

Answer from: Quest

hello from mrbilldoesmath!

answer: x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb

Answer from: Quest

“ a line segment that has the endpoints on the circle and passes through the midpoint is called the diameter. the diameter is twice the size of the radius. a line segment that has its endpoints on the circular border but does not pass through the midpoint is called a chord. a circle is the same as 360 small circle up the number 0 . i hope this .

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