Choose the equivalent system of linear equations that will produce the same solution as the one given below. (1 point) 4x − 2y = 6 2x + y = 5

Choose the equivalent system of linear equations that will produce the same solution as the one given below.

4x - 2y = 6

2x + y = 5

Options:

A) -4x - 2y = 10

-4y = 4

B) -4x - 5y = -1

-7y = 5

C) 3x + 2y = 6

7x = 12

D) 4x + 2y = 10

8x = 16

Option D

The equivalent system of linear equations that will produce the same solution as the one given is 4x + 2y = 10  and 8x = 16

Given system of equations are:

4x - 2y = 6   --------- eqn 1

2x + y = 5  ------- eqn 2

Multiply eqn 2 by 2

2(2x + y = 5)

4x + 2y = 10 --------- eqn 3

Add eqn 1 and eqn 3

4x - 2y + 4x + 2y = 6 + 10

8x = 16

x = 2

Substitute x = 2 in eqn 1

4(2) - 2y = 6

8 - 2y = 6

2y = 8 - 6

2y = 2

y = 1

Thus the solution of given system of equations is (x , y) = (2, 1)

Given system of equations are:

-4x - 2y = 10  ---- eqn 1

-4y = 4  --- eqn 2

Substitute the obtained solution (x, y) = (2, 1) in above equations and check if it makes the equation true

From eqn 2,

-4(1) = 4

Thus this option does not produce the same solution as the one given

-4x - 5y = -1   ----- eqn 1

-7y = 5   ------- eqn 2

Substitute the obtained solution (x, y) = (2, 1) in above equations and check if it makes the equation true

From eqn 2,

Thus this option does not produce the same solution as the one given

3x + 2y = 6  ------ eqn 1

7x = 12 --------- eqn 2

Substitute the obtained solution (x, y) = (2, 1) in above equations and check if it makes the equation true

From eqn 2,

Thus this option does not produce the same solution as the one given

4x + 2y = 10   ------ eqn 1

8x = 16 -------- eqn 2

Substitute the obtained solution (x, y) = (2, 1) in above equations and check if it makes the equation true

From eqn 2,

8(2) = 16

16 = 16

Also,

from eqn 2,

8x = 16

x = 2

substitute x = 2 in eqn 1

4(2) + 2y = 10

8 + 2y = 10

2y = 2

y = 1

Thus solution is (2, 1)

Thus this option produce the same solution as the one given

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.