If a and b are two mutually exclusive events with p(a) = .25 and p(b) = .65,

a) p(a and b) =
b) p( a or b) =
c) p(not a) =
d) p(not b) =
e) p(not (a or b))=
f) p( a and not b) =

 The required probabilities are

(a) 0,  (b) 0.90,  (c) 0.75,  (d) 0.35,  (e) 0.10  and  (f) 0.25.

Step-by-step explanation:  Given that A and B are two mutually exclusive events with P(A) = 0.25 and P(B) = 0.65.

We know that, for any two mutually exclusive events X and Y, we have

(a) Since A and B are mutually exclusive events, so

(b) From Addition theorem of probability, we have

(c) We have

(d) We have

(e) We have

(f) We have

Thus, the required probabilities are

(a) 0,  (b) 0.90,  (c) 0.75,  (d) 0.35,  (e) 0.10  and  (f) 0.25.

this doesn't make sense lol