Find the perimeter and area of this shape!

Area = 7.855 in² ,  perimeter = 11.426 in.

Step-by-step explanation:

The shape consists of two quadrants  which later form a  bigger semicircle and a small semicircle.

To find the area of the shape,

Formula for finding e area of a quadrant                     = πr²/4,

This is because a quadrant is ¹/₄ of a circle

Therefore, are of the two quadrant                             = (3.142 x 2² x 2)/4

                                                                                      = (3.142 x 4 x 2) /4

                                                                                      = 6.284 in².

Area of the smaller half circle                                      = πr²/2, where r = 1 in because the diameter is 2 in.

Recall , 2r = a diameter

                                                                                      = (3.142 x  1²)/2

                                                                                      = 1.571 in²

Therefore total area of the shaded portion                 = 6.284 + 1.571

                                                                                       = 7.855 in².

The perimeter of the of the bigger half circle              = the circumference  

Formula for circumference of a semicircle                  = πd/2 or 2πr/2

                                                                                       = (3.142 x 4)/2

                                                                                       = 6.284 in.

Perimeter of the smaller half circle                               = (3.142 x 2)/2

                                                                                        =  3.142 in.

Perimeter of the shape                                                  = 6.284 + 3.142 + 2

                                                                                        = 11.426 in.

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations: