Can someone do this quick and easy question i need lolol
circle theorems

Step-by-step explanation:

Consider quadrilateral ABDE. This quadrilateral is inscribed in the circle, so the sum of the measures of two opposite angles of quadrilateral is 180°. So,

Consider triangle ABD. The sum of the measures of all interior angles in triangle ABD is 180°, so

Consider triangle ADE. This triangle is isosceles triangle, because AD = DE. Angles adjacent to the base AE are congruent, so

Consider triangle ACE. The sum of the measures of all interior angles in triangle ACE is 180°, so

b

step-by-step explanation:

calculate the scale factor as the ratio of corresponding sides, image to original, that is

scale factor = = = = 1

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!