Aline perpendicular to y=-1/5x+1 and intersects the point (-5,1) what is the equation of this perpendicular line

Step-by-step explanation:

y = -1/5x + 1

the slope here is -1/5a perpendicular line will have a negative reciprocal slope. All that means is flip the slope and change the sign. So our perpendicular slope will have to be 5(because I flipped -1/5, making it -5/1, then I switched the sign...making it 5/1 or just 5)

y = mx + b

slope(m) = 5

(-5,1)...x = -5 and y = 1

now we sub and find b, the y int

1 = 5(-5) + b

1 = - 25 + b

1 + 25 = b

26 = b

so ur equation for the perpendicular line is : y = 5x + 26

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!