The compound inequality for 9 – 4x ≥ 5 or 4(–1 + x) – 6 ≥ 2 is:
Option A is correct.
A compound inequality is one that is formed by combining two simple inequalities. They are derived form of fundamental inequalities.
From the question:
9 – 4x ≥ 5 or 4(–1 + x) – 6 ≥ 2
The first thing to do is to open the brackets and move the like terms to the same sides.
So,
9 - 5 ≥ 4x or -4 + 4x - 6 ≥ 2
4 ≥ 4x or -10 + 4x ≥ 2
4 ≥ 4x or 4x ≥ 10 + 2
4 ≥ 4x or 4x ≥ 12
4x ≥ 4 or 4x ≥ 12
Divide both sides by 4
x ≥ 1 or x ≥ 3
Therefore, the compound inequality of 9 – 4x ≥ 5 or 4(–1 + x) – 6 ≥ 2 is:
x ≥ 1 or x ≥ 3
Learn more about compound inequality here:
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