Prove that: –7 is not the arithmetic square root of 49

–7 is not the arithmetic square root of 49 only in case we are taking it for natural number.

Step-by-step explanation:

The square root of x is that number which on squaring gives the result as x.For example, the square root of 4 is +2 or -2. Because on squaring +2 or -2 we get the number 4.Similarly for the case of 49, the square root might be both +7 or -7.But if we are taking it as a natural number then -7 is not valid. Like for length, quantity or other sort of things -7  is not the arithmetic square root of 49.