Find the cross product < –1, –3, –8> × < 7, 4, –5> . is the resulting vector perpendicular to the given vectors?

The cross product is 47 i - 61 j + 17 k.

Step-by-step explanation:

Given that-

a = < -1, -3, -8 > , b = < 7, 4, -5 >

The cross product is

a × b =

        = i ( - 3 × -5 - 4 × -8 ) - j ( -1 × -5 - (-8) × 7 ) + k ( -1 × 4 - 7 × -3 )

        = i ( 15 + 32 ) -j ×( 5 + 56 ) + k ( -4 + 21 )

        = i ( 47) - j (61 ) + k (17)

        = 47 i -61 j + 17 k

As we know that if two vectors A & B are perpendicular then

A . B = 0

So here only the given vector b = < 7,4, -5> is perpendicular to the resulting vector .

your answer would be 10x - 1

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1