Maximize
p
=
60
x
+
50
y
p
=
60
x...
Mathematics, 13.01.2020 08:31 roadrnr8970
Maximize
p
=
60
x
+
50
y
p
=
60
x
+
50
y
.
⎧
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎨
⎪
⎪
⎪
⎪
⎪
⎪
⎪
⎩
x
+
y
≤
80
5
x
+
10
y
≤
560
50
x
+
20
y
≤
1600
x
≥
0
y
≥
0
{
x+y≤80 5x+10y≤560 50x+20y≤1600 x≥0 y≥0
use the simplex method to solve the problem. use s, t, and u as your slack variables for the first, second, and third inequalities respectively. use the final simplex tableau to identify the values below.
x =
y =
s =
t =
u =
p =
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