Suppose you select 2 letters at random from the word compute without replacement. find each probability. p(2 vowels)

1/7

Step-by-step explanation:

The word "compute" has 7 letters, 3 of which are vowels.

The probability that the first letter is a vowel is 3/7.

There's no replacement, so there are 6 letters left, 2 of which are vowels.

The probability that the second letter is a vowel is 2/6.

The probability of 2 vowels is therefore:

P = (3/7) (2/6)

P = 1/7

81 seats

step-by-step explanation:

if you multiply 0.65 times 125 then you get 81.5 seats. well since you can't have half of a seat you have to round down and get 81 seats in the no children zones. that leave 44 seats outside of the no children zone.

i'm sorry i don't know

step-by-step explanation: