Asecurity alarm requires a four-digit code. the code can use the digits 0-9 and the digits cannot be repeated
which expression can be used to determine the probability of the alarm code beginning with a number greater than 72
(@p})(p3)
10p4
(25)(c3)
1004
60p; ) (gp3)
10p4
1064)(c3)
10c

₂P₁ ₉P₃ / ₁₀P₄

Step-by-step explanation:

There are 2 digits greater than 7 (8 and 9).  The number of ways you can select 1 digit from 2 is ₂P₁.

After the first digit is selected, there are 9 digits left.  The number of ways you can select 3 digits from 9 is ₉P₃.

The total number of ways you can select 4 digits from 10 is ₁₀P₄.

Therefore, the probability that the code starts with a number greater than 7 is:

₂P₁ ₉P₃ / ₁₀P₄

is this part of a question or something