Find the equation of the line parallel to the line graphed that passes through the point (6,-1).
a) y =
1
3
x + 1
b) y = -
1
3
x + 1
c) y = -
1
3
x + 6
d) y = -
7
6
x + 6

180°

step-by-step explanation:

sum of equilateral triangle=180°

< n=60°

< m=120°°[angle supplementary of equilateral angle]

< m+< r+< x=360°(sum of exterior angle of triangle)

i don't think there is enough