You are choosing numbers from the set s ={a, b, c, d, e, f, g, h}. let x = the number of ways to choose 3 letters from s without replacement (order doesn’t matter). which option below is equivalent to x?

Given set S = {A, B, C, D, E, F, G, H}
There are 8 elements in set S and we are to choose 3 letters at random, the number of ways to choose such is x. It is simply similar to choosing 5 letters at random, which is also equal to x. Since order doesn't matter, n! / (n-m)! where n = 8 and m = 3, which is 336 ways. 

Pp= 50 pounds of apples