![\int_{1}^{\infty} 6e^{-x} dx= -6 [0 -\frac{1}{e}] =\frac{6}{e}](/tpl/images/0454/6856/158cd.png)
![\int_{1}^{\infty} 6e^{-x} dx= -6 [\lim_{x\to\infty} \frac{1}{e^x} - e^{-1}]](/tpl/images/0454/6856/e3b3d.png)
![\int_{1}^{\infty} 6e^{-x} dx= -6 [0 -\frac{1}{e}]=\frac{6}{e}](/tpl/images/0454/6856/2dde0.png)
Find the value of the integral that converges.
∫^[infinity]_1 6e^-x dx....
Mathematics, 14.01.2020 19:31 litttyyyu33411
Find the value of the integral that converges.
∫^[infinity]_1 6e^-x dx.
Answers: 3
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