Xavier, yvonne, and zelda each try independently to solve a problem. if their individual probabilities for success are 1/4, 1/2 and 5/8, respectively, what is the probability that xavier and yvonne, but not zelda, will solve the problem?

a. 11/8
b. 7/8
c. 9/64
d. 5/64
e. 3/64

The probability that Xavier and Yvonne can solve a problem but Zelda cannot is

Step-by-step explanation:

We are given:

Probability of success of Xavier,

Probability of failure of Xavier,

Probability of success of Yvonne,

Probability of failure of Yvonne,

Probability of success of Zelda,

Probability of failure of Zelda,

We need to calculate:

The probability that Xavier and Yvonne can solve the problem but Zelda cannot, we use:

Hence, the probability that Xavier and Yvonne can solve a problem but Zelda cannot is

a complex number is a number that can be expressed in the form a + bi, where a and b are real numbers, and i is a solution of the equation x2 = −1. because no real number satisfies this equation, i is called an imaginary number. has no real solution, since the square of a real number cannot be negative.

use an equation of ratios to determine the amount of gas needed to fill the tank.

    0.2             0.8

  =    

288.75             x

                                                              231 gal

so, 0.2x = (0.8)(288.75 gal), and x = = 1155 gal.

                                                                0.2

it would take 1155 gal. to fill the tank.

the cost would be

1155 gal         $3

* = $3465   (answer)

      1           1 gal

hope this you