Find an equation of a sphere with center (2,-3,6) that touch (a) the xy-plane, (b) the yz-plane, (c) the xz-plane.

Step-by-step explanation:

To find the equation of a sphere with center (2,-3,6) that touch

(a) the xy-plane,

The equation of xy plane is z=0

Hence the radius would be distance from z=0 perpendicular to xy plane = z coordinate =6

Equation is

(b) the yz-plane,

The equation of yz plane is x=0

Hence the radius would be distance from x=0 perpendicular to yz plane = x coordinate =2

Equation is

(c) the xz-plane.

The equation of zx plane is y=0

Hence the radius would be distance from y=0 perpendicular to zx plane = |y coordinate| =3

Equation is

the two may have that, even a breakdown is probably offered