Drug reaction the intensity of the reaction to a certain drug, in appropriate units, is given by
r(t)=te-0.1t,
where t is time (in hours) after the drug is administered. find the average intensity during the following hours.
a. second hour
b. tewlth hour
c. twenty-fourth hour.

a) A=0.86

b) A=2.81

c) A=2.88

Step-by-step explanation:

The average of a functions can be written as:

(1)

a.) The second hour means that the interval of time is from 0 to 2 hours, so a=0 and b=2. Using the equation (1) we can calculate the average intensity.

Using integration by parts we can solve it.

,

,

(2)

Therefore, the average intensity at the second hour will be:

b) We can use the equation (2) to solve it. In this case the limits of integration will be a = 0 and b = 12 hours.  

Therefore, the average intensity at the twelfth hour will be:

c) Finally, here a = 0 and b = 24 hour.

Therefore, the average intensity at the twenty-fourth hour will be:

I hope it helps you!

a; x = 0.5

step-by-step explanation:

-10x = -5

x = 0.5

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

i hope this you, and have a wonderful day!