Using a property of logarithms demonstrate that
in x/in y≠ inx/y = in x - in y
by using a spreadsheet to complete the table.
x y inx/iny inx/y in x - in y
1 2
3 4
10 5
4 0.5

Dividing logarithms is not the same as dividing the arguments of a logarithm.

Step-by-step explanation:

1) If we divide two logarithms then we'll find a value. This is not the same as dividing two arguments of the same base logarithms.

For example:

Then

2) Completing the table below to show it clearly:

b. hannah is playing with her cousin at

where is the graph? need more info