Determine whether the improper integral converges or diverges, and find the value of each that converges.
∫^[infinity]_1 ln |x| dx

Answer

Given

Improper Integral I is given as  

using ilate rule

now,

putting limits of integrals

now, we are not able to find the solution of the above equation.

hence, the integral donot converges to a single point.

so, we can say that the integral is diverging in nature.

x^6

step-by-step explanation:

this is correct because:

x-6=0

0*x=0

so

x^6

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47