Finding an equation of a tangent line in exercise, use implicit differentiation to find an equation of the tangent line to the graph of the function at the given point.
x + y - 1 = ln(x2 + y2); (1, 0)

Equation of tangent line at point (1,0) to given function is

y=x-1

Step-by-step explanation:

Equation of tangent line is

                                   y-y₁=m(x-x₁)-----(1)

where m is slope of line and can be found by implicitly differentiating the given function w.r.to x

which is slope of tangent line. At (1,0) equation of tangent line is

could you provide figure.