Suppose that a2 = 0 for some matrix a. prove that the only possible eigenvalues of a are then 0.

The eigenvector of A is not equal to zero, then we can say λ or λ = 0. Therefore,  the only possible eigenvalues of A are 0.

Step-by-step explanation:

If we assume that λ is the eigenvalue of the matrix A and the eigenvector of the matrix A is ⁻ˣ. Therefore:

For

we have:

⁻0 = [⁰₀⁰₀][⁻ˣ] = *[⁻ˣ] = Aλ[⁻ˣ] = λ[⁻ˣ]

In the expression above, ⁻ˣ is not equal to zero, then λ = 0 or  λ is = 0. This shows that the only possible eigenvalues of A are zero '0'

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.