The total length of pencils a, b and c is 29 cm. pencil a is 11 cm shorter then pencil b, and pencil b is twice as long a pencil c. how long is pencil a?

The length of pencil A is 5 cm

Solution:

Let the length of pencil A be "x"

Let the length of pencil B be "y"

Let the length of pencil C be "z"

The total length of pencils A, B and C is 29 cm

Therefore,

length of pencil A + length of pencil B + length of pencil C = 29

x + y + z = 29 ------------ eqn 1

Pencil A is 11 cm shorter then pencil B

x = y - 11 ------- eqn 2

Pencil B is twice as long a pencil C

y = 2z

------ eqn 3

Substitute eqn 2 and eqn 3 in eqn 1

Substitute y = 16 in eqn 2

x = 16 - 11

x = 5

Thus length of pencil A is 5 cm

12cm

the answer is d

teleportation

step-by-step explanation: