If a sample has 25 observations and a 99% confidence estimate for μ is needed, the appropriate value of the t-multiple required is . place your answer, rounded to 3 decimal places, in the blank. for example, 3.456 would be an appropriate entry.

Two tailed t = 2.797

One tailed t = 2.492

Step-by-step explanation:

The t-value can be defined as the ratio of the difference between the mean of the two sample sets and the difference that exists within the sample sets.

t at 99% confidence interval. For;

degree of freedom df = 25-1 = 24

Two sided test

t ( 99% +1/2% = 99.5)

Check t at 0.995 df = 24

t = 2.797

One tail test

t ( at 0.990) df = 24

t = 2.492

it is b)

hope this : )

step-by-step explanation:

.632

step-by-step explanation:

6 * 1/10 = 3/5

3*0.01 = 0.03

3/5 + 0.03 = .63

2*0.002 = .002

.63 + 0.002 = .632